Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 61 of Exercise 10A
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61
Solve each of the following quadratic equations:
Given:
taking LCM
3x2 - 33x + 87 = 5x2 - 60x + 175 cross multiplying
2x2 - 27x + 88 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = 2 b = - 27 c = 88
= 2.88 = 176
And either of their sum or difference = b
= - 27
Thus the two terms are - 16 and - 11
Sum = - 16 - 11 = - 27
Product = - 16. - 11 = 176
2x2 - 27x + 88 = 0
2x2 - 16x - 11x + 88 = 0
2x(x - 8) - 11(x - 8) = 0
(x - 8) (2x - 11) = 0
(x - 8) = 0 or (2x - 11) = 0
Hence the roots of equation are 
