Solve each of the following quadratic equations:
Given:
taking LCM
cross multiplying
3x2 - 5x = 6x2 - 18x + 12
3x2 - 13x + 12 = 0
Using the splitting middle term - the middle term of the general equation is divided in two such values that:
Product = a.c
For the given equation a = 3 b = - 13 c = 12
= 3.12 = 36
And either of their sum or difference = b
= - 13
Thus the two terms are - 9 and - 4
Sum = - 9 - 4 = - 13
Product = - 9. - 4 = 36
3x2 - 13x + 12 = 0
3 x2 - 9x - 4x + 12 = 0
3x (x - 3) - 4(x - 3) = 0
(x - 3) (3x - 4) = 0
Hence the roots of equation are