Solve each of the following equations by using the method of completing the square:

x^{2} - 6x + 3 = 0

Given: x^{2} - 6x + 3 = 0

x^{2} - 6x = - 3

x^{2} - 2.x.3 + 3^{2} = - 3 + 3^{2} (adding 3^{2} on both sides)

(x - 3)^{2} = - 3 + 9 = 6 using a^{2} - 2ab + b^{2} = (a - b)^{2}

(taking square root on both sides)

Hence the roots of equation are

1