Solve each of the following equations by using the method of completing the square:

3x^{2} - 2x - 1 = 0

Given: 3x^{2} - 2x - 1 = 0

9x^{2} - 6x = 3 (multiplying both sides by 3)

(adding on both sides)

using a^{2} - 2ab + b^{2} = (a - b)^{2}

(taking square root on both sides)

3x - 1 = 2 or 3x - 1 = - 2

3x = 3 or 3x = - 1

Hence the roots of equation are

9