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Find the nature of the roots of the following quadratic equations:
5x2 – 4x + 1 = 0
Given: 5x2 – 4x + 1 = 0
Comparing with standard quadratic equation ax2 + bx + c = 0
a = 5, b = – 4, c = 1
Discriminant D = b2 – 4ac
= (– 4)2 – 4.5.1
= 16 – 20 = – 4 < 0
Hence the equation has no real roots.