Given equation is (2p + 1)x² – (7p + 2)x + (7p – 3) = 0

Comparing with standard quadratic equation ax² + bx + c = 0

a = (2p + 1) b = – (7p + 2) c = (7p – 3)

Given that the roots of equation are real and equal

Thus D = 0

Discriminant D = b² – 4ac = 0

[ – (7p + 2)]² – 4.(2p + 1).(7p – 3) = 0 using (a + b)² = a² + 2ab + b²

(49p² + 28p + 4) – 4(14p² + p – 3) = 0

49p² + 28p + 4 – 56p² – 4p + 12 = 0

– 7p² + 24p + 16 = 0

7p² – 24p – 16 = 0

7p² – 28p + 4p – 16 = 0

7p(p – 4) + 4(p – 4) = 0

(7p + 4)(p – 4) = 0

(7p + 4) = 0 or (p – 4) = 0

The values of p are for which roots of the quadratic equation are real and equal.