The area of a right – angled triangle is 96 sq metres. If the base is three times the altitude, find the base.

Let the altitude of the triangle be x m

The base will be 3x m

Area of triangle = 1/2. Base. altitude

1/2.3x.x = 96

x^{2} = 64

x = 8 or – 8 taking square root

Value of x cannot be negative

Thus the altitude of the triangle be 8 m

The base will be 3.8 = 24m

67