RS Aggarwal - Mathematics

Book: RS Aggarwal - Mathematics

Chapter: 10. Quadratic Equations

Subject: Maths - Class 10th

Q. No. 33 of Exercise 10F

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33

Show that x = - 3 is a solution of x2 + 6x + 9 = 0.

If x = - 3 is a solution then it must satisfy the equation

x2 + 6x + 9 = 0


LHS = x2 + 6x + 9


= ( - 3)2 + 6. - 3 + 9


= 9 - 18 + 9


= 18 - 18


= 0 = RHS


Thus x = - 3 is a solution of the equation


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