Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 52 of Exercise 10F
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52
Solve: 4x2 + 4bx – (a2 – b2) = 0.
Using splitting middle term, the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation 
And either of their sum or difference = b
= 
Thus the two terms are 
Difference = 
= 
= 
Product = 
= 
using 
= 
using 
2x[2x + (a + b)] - (a - b)[2x + (a + b)] = 0
[2x - (a - b)][2x + (a + b)] = 0
[2x - (a - b)] = 0 or [2x + (a + b)] = 0
2x = (a - b) or 2x = - (a + b)
Hence roots of equation are 
Chapter Exercises
More Exercise Questions
46
Solve: 
