Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 53 of Exercise 10F
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53
Solve: x2 + 5x – (a2 + a – 6) = 0
Using splitting middle term, the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = 1 b = 5 c = 
= 
And either of their sum or difference = b
= 
Thus the two terms are 
Difference = 
= 
Product = 
= 
x[x + (a + 3)] - (a - 2)[x + (a + 3)] = 0
[x - (a - 2)][x + (a + 3)] = 0
[x - (a - 2)] = 0 or [x + (a + 3)] = 0
x = (a - 2) or x = - (a + 3)
Hence roots of equation are x = (a - 2)or - (a + 3)
Chapter Exercises
More Exercise Questions
46
Solve: 
