A sector of 56°, cut out from a circle, contains 17.6 cm2. Find the radius of the circle.
Given:
Angle of the sector = 56°
Area of the sector = 17.6 cm2
Let the radius of the circle be ‘r’.
∵ Area of sector = × πr2
∴ 17.6 = × × r2
r2 = × × 17.6
r2 = 36
r = √36
r = 6 cm
Hence, the radius of the circle is 6 cm.