A sector of 56°, cut out from a circle, contains 17.6 cm2. Find the radius of the circle.

Given:

Angle of the sector = 56°


Area of the sector = 17.6 cm2


Let the radius of the circle be ‘r’.


Area of sector = × πr2


17.6 = × × r2


r2 = × × 17.6


r2 = 36


r = √36


r = 6 cm


Hence, the radius of the circle is 6 cm.


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