In the given figure, ABCD is a square of side 4 cm. A quadrant of a circle of radius 1 cm is also drawn. Find the area of the shaded region.

Given:

Side of the square = 4 cm

Radius of the quadrants at the corners = 1 cm

Radius of the circle in the centre = 1 cm

∵ 4 quadrants = 1 circle

∴ There are 2 circles of radius 1 cm

Area of square = side × side

= 4 × 4 = 16 cm^{2}

Area of 2 circles = 2 × πr^{2}

= 2 × × 1 × 1 = cm^{2}

∵ Area of shaded region = Area of square – Area of 2 circles

= 16 -

= = cm^{2} = 9.7 cm^{2}

__Hence, the area of shaded region is 9.72 cm ^{2}.__

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