## Book: RS Aggarwal - Mathematics

### Chapter: 18. Area of Circle, Sector and Segment

#### Subject: Maths - Class 10th

##### Q. No. 27 of Exercise 18A

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27
##### From a rectangular sheet of paper ABCD wit AB = cm and AD = 28 cm, a semicircular portion wit BC as diameter is cut off. Find the area of the remaining paper.

Given:

Length of rectangular sheet of paper = 40 cm

Breadth of rectangular sheet of paper = 28 cm

Radius of the semicircular cut out = 14 cm

Area of rectangle = length × breadth

Area of rectangular sheet of paper = 40 × 28

= 1120 cm2

Area of semicircle = πr2

Area of semicircular cut out = × × 14 × 14

= 22 × 14 = 308 cm2

Thus, the area of remaining sheet of paper = Area of rectangular sheet of paper – Area of semicircular cut out

= 1120 – 308 = 812 cm2

Hence, the area of remaining sheet of paper is 812 cm2.

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