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In the given figure PQSR represents a flower be. If OP = 21 m and OR = 14 m, find the area of the flower bed.
Given:
OP = 21 m = r1
OR = 14 m = r2
Let the quadrants made by outer and inner circles be Q1 and Q2, with radius r1 and r2 respectively.
Then, Area of flower bed = Area of Q1 – Area of Q2
∵ Area of Quadrant = πr2
∴ Area of Q1 = πr12
= ×
× 21 × 21
= m2
Similarly, Area of Q2 = πr22
= ×
× 14 × 14
= m2
Thus, Area of flower bed = -
= = 192.5 m2
Hence, the area of the flower bed is 192.5 m2.