Given:

OP = 21 m = r₁

OR = 14 m = r₂

Let the quadrants made by outer and inner circles be Q₁ and Q_2, with radius r₁ and r₂ respectively.

Then, Area of flower bed = Area of Q₁ – Area of Q₂

∵ Area of Quadrant = πr²

∴ Area of Q₁ = πr₁²

= × × 21 × 21

= m²

Similarly, Area of Q₂ = πr₂²

= × × 14 × 14

= m²

Thus, Area of flower bed = -

= = 192.5 m²

Hence, the area of the flower bed is 192.5 m².