A path of 8 m width runs around the outside of a circular park whose radius is 17 m. Find the area of the path.

Given radius of circular park = R = 17 m

Width of the circular path outside the park = d = 8 m

Therefore, the radius of the outer circle = R’ = R + d

Outer radius = R’ = 17 + 8

R’ = 25 m

Area of inner circle = πR^{2} and,

Area of outer circle = πR’^{2}

Area of path = Area of outer circle – Area of inner circle

= πR’^{2} – πR^{2} (put values of R’ & R)

= π(25^{2}) – π(17^{2})

= π(25^{2} – 17^{2}) (taking π common from R.H.S)

= π(625 – 289)

(put π = 22/7)

= 7392/7

= 1056 m^{2}

The area of the path is 1056 m^{2}.

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