Given radius of circular park = R = 17 m

Width of the circular path outside the park = d = 8 m

Therefore, the radius of the outer circle = R’ = R + d

Outer radius = R’ = 17 + 8

R’ = 25 m

Area of inner circle = πR² and,

Area of outer circle = πR’²

Area of path = Area of outer circle – Area of inner circle

= πR’² – πR² (put values of R’ & R)

= π(25²) – π(17²)

= π(25² – 17²) (taking π common from R.H.S)

= π(625 – 289)

(put π = 22/7)

= 7392/7

= 1056 m²

The area of the path is 1056 m².