## Book: RS Aggarwal - Mathematics

### Chapter: 18. Area of Circle, Sector and Segment

#### Subject: Maths - Class 10th

##### Q. No. 22 of Exercise 18B

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22
##### A rope by which a cow is tethered is increased from 16 m to 23 m. How much additional ground does it have now to graze?

Here the increase in the length of the rope simply means that there is increase in the radius of the circle within which cow can graze. Now to find the additional area available for grazing can be easily be found by simply subtracting the initial area available for grazing from the new area available.

Initial radius = r = 16 cm

Increased radius = R = 23 cm

Additional ground available = Area of new ground – Initial area eqn1

Initial area of ground = π(r2)

Initial area of ground = π(162)

Initial area of ground = 256π eqn2

Area of new ground = πR2

Area of new ground = π(232)

Area of new ground = 529π eqn3

Now put the values of equation 2 and 3 in equation 1

Additional area of ground available = 529π – 256π

Additional area available = (529 – 256)π (Taking π common)

(22×273)/7

= 6006/7

= 858 cm2

The additional ground available is 858 cm2.

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