A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the minor segment. [Use π = 3.14.]

Given the radius of the circle = 42 cm

Central angle of the sector = θ = 90°

Area of the minor segment = Area of sector – area of the right angle triangle

⇒ Area of the sector = 25×3.14

∴ Area of the sector = 78.5 cm^{2}→ eqn1

∴ Area of triangle = 50 cm^{2}→ eqn2

Area of the minor segment = 78.5 – 50 (from eqn1, eqn2)

∴ Area of the minor segment = 28.5 cm^{2}

Area of the minor segment is 28.5 cm^{2}.

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