## Book: RS Aggarwal - Mathematics

### Chapter: 18. Area of Circle, Sector and Segment

#### Subject: Maths - Class 10th

##### Q. No. 52 of Exercise 18B

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52
##### The area of an equilateral triangle is 49√3 cm2. Taking each angular point as centre, circles are drawn with radius equal to half the length of the side of the triangle. Find the area of the triangle not included in the circles. [Take √3 = 1.73.]

Each angle of triangle = θ = 60°

Area of triangle not included in circles = Area of triangle – Area of all sectors

Area of all 3 sectors area equal as all the three circles are having same radius which is equal to the half of the side of the equilateral triangle.

Let the side of equilateral triangle be = a cm

a = 7×2

a = 14 cm

So radius of the circles = 7 cm

Area of all 3 sectors = 77 cm2 eqn1

Area of triangle not included = (49×1.73) - 77

Area of triangle not included = 84.77 – 77

Area of triangle not included = 7.77 cm2

Area of triangle not included in circles is 7.77 cm2.

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