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12

If the sum of the circumferences of two circles with radii R_{1} and R_{2} is equal to the circumference of a circle of radius R then

Let three circles be C_{1}, C_{2} and C

Circumference of circle C = Circumference of circle C_{1} + Circumference of circle C_{2}

⇒ 2πR = 2πR_{1} + 2πR_{2}

R = R_{1} + R_{2}