If the circumference of a circle and the perimeter of a square are equal then
Let the length of the side of the square be a
Let the radius if circle be r
Perimeter of circle = 2πr
Perimeter of square = 4a
Perimeter of circle = Perimeter of square
2πr = 4a
a = π × r/2
Area of a square = a2
= (π × r/2)2 = π/4 × πr2
Area of circle = πr2
Seeing the co-efficient of πr2
1 > π/4 ∴ πr2 > π/4 × πr2
So, (area of the circle) > (area of the square)