Book: RS Aggarwal - Mathematics
Chapter: 18. Area of Circle, Sector and Segment
Subject: Maths - Class 10th
Q. No. 24 of Multiple Choice Questions (MCQ)
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24
A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given, π = 3.14) is
Radius of Circle = R = 10 cm
Area of minor Segment = Area of sector subtending 90° – Area of triangle ABC
Area of sector subtending 90° = 
= 3.14 × 10 × 10 × 90/360 cm2
= 78.5 cm2
Area of triangle ABC = 1/2 × AC × BC
= 1/2 × 10 × 10 cm2 = 50 cm2
Area of Minor segment = 78.5 cm2 – 50 cm2
= 28.5 cm2
