A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given, π = 3.14) is

Question

Philoid · Accepted Answer

Radius of Circle = R = 10 cm

Area of minor Segment = Area of sector subtending 90° – Area of triangle ABC

Area of sector subtending 90° = = 3.14 × 10 × 10 × 90/360 cm²

= 78.5 cm²

Area of triangle ABC = 1/2 × AC × BC

= 1/2 × 10 × 10 cm² = 50 cm²

Area of Minor segment = 78.5 cm² – 50 cm²

= 28.5 cm²