RS Aggarwal - Mathematics

Book: RS Aggarwal - Mathematics

Chapter: 18. Area of Circle, Sector and Segment

Subject: Maths - Class 10th

Q. No. 1 of Formative Assessment (Unit Test)

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1

In the given figure, a square OABC has been inscribed in the quadrant OPBQ. If OA = 20 cm then the area of the shaded region is [take π = 3.14]

Length of side of square = OA = 20 cm


Radius of Quadrant = OB = cm = 20√2 cm


Area of Quadrant = πR2 × θ/360 = 3.14 × 20√2 × 20√2 × 90/360 = 628 cm2


Area of Square = a2 = 202 cm2 = 400 cm2


Area of Shaded region = Area of Quadrant - Area of Square


= 628 cm2 – 400 cm2


= 228 cm2

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