In the given figure, ABCD is a square each of whose sides measures 28 cm. Find the area of the shaded region. [Take π = 22/7]

Length of the sides of square = 28 cm


Area of square = a2 = 282 cm2


= 784 cm2


Since, all the circles are identical so, they have same radius


Let the radius of circle be R cm


From the figure 2R = 28 cm


R = 28/2 cm


R = 14 cm


Quadrant of a circle subtends 90° at the centre.


Area of quadrant of circle =


= 22/7 × 14 × 14 × 90°/360° cm2 = 154 cm2


Area of 4 quadrants of circle = 154 × 4 cm2 = 616 cm2


Area of shaded region = Area of square – Area of 4 quadrants of circle


= 784 cm2 – 616 cm2


= 168 cm2


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