In the given figure, ABCD is a square each of whose sides measures 28 cm. Find the area of the shaded region. [Take π = 22/7]

Length of the sides of square = 28 cm

Area of square = a^{2} = 28^{2} cm^{2}

= 784 cm^{2}

Since, all the circles are identical so, they have same radius

Let the radius of circle be R cm

From the figure 2R = 28 cm

R = 28/2 cm

R = 14 cm

Quadrant of a circle subtends 90° at the centre.

Area of quadrant of circle =

= 22/7 × 14 × 14 × 90°/360° cm^{2} = 154 cm^{2}

Area of 4 quadrants of circle = 154 × 4 cm^{2} = 616 cm^{2}

Area of shaded region = Area of square – Area of 4 quadrants of circle

= 784 cm^{2} – 616 cm^{2}

= 168 cm^{2}

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