Find the area of the triangle whose sides are 42 cm, 34 cm and 20 cm. Also, find the height corresponding to the longest side.
Given: Side 1 = a (let) = 42 cm
Side 2 = b (let) = 34 cm
Side 3 = c (let) = 20 cm
We know that,
Area of a scalene triangle = √(s(s-a) (s-b) (s-c))
Where,
⇒ s = 48 cm
Now,
Area of a scalene triangle = √(48cm × (48-42)cm × (48-34)cm × (48-20)cm)
= √(48cm × 6cm × 14cm × 28cm)
= √112896 cm2
= 336 cm2
Clearly,
Length of longest side = 42 cm
Now,
We know that,
Area of a triangle = 1/2 × Base × Height
⇒ 336 cm2 = 1/2 × 42 cm × Height
⇒ 336 cm2 = 21 cm × Height
⇒ Height = 16 cm