Find the area and perimeter of an isosceles right triangle, each of whose equal sides measures 10 cm. [Take √2 = 1.41.]
Given: Equal sides (i.e., base and perpendicular) = 10 cm
We know that,
Area of a triangle = 1/2 × Base × Height
Area of a triangle = 1/2 × 10 cm × 10 cm
Area of a triangle = 50 cm2
Now,
Base2 + Perpendicular2 = Hypotenuse2
⇒ 102 + 102 = Hypotenuse2
⇒ Hypotenuse2 = 100 + 100
⇒ Hypotenuse2 = 200 cm2
⇒ Hypotenuse= 10√2 cm
⇒ Hypotenuse= 14.1 cm
Now,
Perimeter of triangle = 10 + 10 + 14.1 cm
= 24.1 cm