Find the area and perimeter of an isosceles right triangle, each of whose equal sides measures 10 cm. [Take √2 = 1.41.]

Given: Equal sides (i.e., base and perpendicular) = 10 cm



We know that,


Area of a triangle = 1/2 × Base × Height


Area of a triangle = 1/2 × 10 cm × 10 cm


Area of a triangle = 50 cm2


Now,


Base2 + Perpendicular2 = Hypotenuse2


102 + 102 = Hypotenuse2


Hypotenuse2 = 100 + 100


Hypotenuse2 = 200 cm2


Hypotenuse= 10√2 cm


Hypotenuse= 14.1 cm


Now,


Perimeter of triangle = 10 + 10 + 14.1 cm


= 24.1 cm


19