Find the length of the diagonal of a square whose area is 128 cm2. Also find the perimeter.
Given:
Area = 128 cm2
Let the side of square be s
Area of square = 1/2 × Diagonal2
⇒ 128 = 1/2 × Diagonal2
⇒ Diagonal2 = 2 × 128
⇒ Diagonal2 = 256
⇒ Diagonal= 16 cm
Area of square = side2
⇒ 128 m2 = s2
⇒ s = 8√2 cm
⇒ s = 11.28 cm
Therefore,
Perimeter of square = 4 × 11.28
= 45.12 cm