In the given figure, ABCD is a quadrilateral in which diagonal BD = 24 cm, AL ⊥ BD and CM ⊥BD such that AL = 9 cm and CM = 12 cm. Calculate the area of the quadrilateral.
Given:
BD = 24 cm
AL = 9 cm
CM = 12 cm
In ∆ADB,
Area of ∆ADB = 1/2 × BD × AL
= 1/2 × 24 cm × 9 cm
= 108 cm2
In ∆CDB,
Area of ∆CDB = 1/2 × BD × CM
= 1/2 × 24 cm × 12 cm
= 144 cm2
Now,
Area of quadrilateral ABCD = Area of ∆ADB + Area of ∆ADB
= 108 cm2 + 144 cm2
= 252 cm2