The perimeter of a rhombus is 60 cm. If one of its diagonals is 18 cm long, find (i) the length of the other diagonal, and (ii) the area of the rhombus.

Given:


Perimeter of rhombus = 60 cm


Length of diagonal 1 (d1) = 18 cm


Let, Length of diagonal 2 be d2



(i) Perimeter of rhombus = 4 × side


60 = 4 × side



Now,


Side of rhombus = 1/2 × √(d12 + d22)


15 = 1/2 × √(182 + d22)


15 = 1/2 × √(324 + d22)


15 × 2 = √(324 + d22)


30 = √(324 + d22)


Squaring both sides,


900 = 324 + d22


900-324 = d22


d22 = 576


d2 = 24


Therefore,


Length of other diagonal = 24 cm


(ii) Area of rhombus = 1/2 × d1 × d2


= 1/2 × 18 cm × 24 cm


= 216 cm2


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