The length of a rectangle is thrice its breadth and the length of its diagonal is 8√10 cm. The perimeter of the rectangle is

Given: Length of rectangle (l) = 3 × breadth(b) = 3b


Diagonal of rectangle = 8√10 m



We know that,


Base2 + Perpendicular2 = Hypotenuse2


b2 + (3b)2 = (8√10) 2


b2 + 9b2 = 640


10b2 = 640



b2 = 64


b = 8 cm


Therefore,


l = 3b = 24 cm


Hence,


Perimeter of a rectangle = 2(length + breadth)


= 2(24 + 8)


= 64 cm

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