The length of a rectangle is thrice its breadth and the length of its diagonal is 8√10 cm. The perimeter of the rectangle is
Given: Length of rectangle (l) = 3 × breadth(b) = 3b
Diagonal of rectangle = 8√10 m
We know that,
Base2 + Perpendicular2 = Hypotenuse2
⇒ b2 + (3b)2 = (8√10) 2
⇒ b2 + 9b2 = 640
⇒ 10b2 = 640
⇒ b2 = 64
⇒ b = 8 cm
Therefore,
l = 3b = 24 cm
Hence,
Perimeter of a rectangle = 2(length + breadth)
= 2(24 + 8)
= 64 cm