One side of a rhombus is 20 cm long and one of its diagonals measures 24 cm. The area of the rhombus is
Given:
Side = 24 cm
Length of diagonal 1 (d1) = 20 cm
Let, Length of diagonal 2 be d2
We know that,
Side of rhombus = 1/2 × √(d12 + d22)
⇒ 20 = 1/2 × √(242 + d22)
⇒ 20 × 2 = √(576 + d22)
⇒ 40 = √(576 + d22)
Squaring both sides,
⇒ 1600 = 576 + d22
⇒ d22 = 1024
⇒ d2 = 32 cm
Now,
Area of rhombus = 1/2 × d1 × d2
= 1/2 × 24 × 32
= 384 cm2