Find the area of an isosceles triangle each of whose equal side is 13 cm and whose base is 24 cm.

Question

Philoid · Accepted Answer

Given:

Side AB = Side AC = 13 cm

Base = 24 cm

In ∆ADC (right-angled),

DC = 12 cm

By Pythagoras theorem,

AD² + DC² = AC²

⇒ AD² = AC² - DC²

⇒ AD² = 13² - 12²

⇒ AD² = 169 – 144 = 25

⇒ AD = 5 cm

Now,

Area of triangle = 1/2 × base × height

= 1/2 × BC × AD

= 1/2 × 24 × 5

= 60 cm²