If a pole 12 m high casts a shadow 4√3 m long on the ground then the sun's elevation is

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Let AB be the pole and BC be its shadow. Join A and C. Given that, AB = 12m, BC = 4√3m. We get a right-angled triangle ∆ABC, right angled at B. ACB is the angle of elevation of the sun. We will use the trigonometric ratio tan taking AB as the height and BC as the base.


In ∆ABC,



or,



since we know that tanθ is √3 whenever θ = 60°.


So, the correct option is (A).

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