In the given figure, DE || BC. If DE = 3 cm, BC = 6 cm and ar (ΔADE) = 15 cm2, find the area of ΔABC.
It is given that DE || BC
∴∠ ADE = ∠ ABC (Corresponding angles)
∠ AED = ∠ ACB (Corresponding angles)
So, by AA similarity criterion ΔADE ~ ΔABC
We know that if two triangles are similar then the ratio of their areas is equal to the ratio of the squares of their corresponding sides.
Hence, proved.