Find the length of each side of a rhombus whose diagonals are 24 cm and 10 cm long.

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ABCD is a rhombus where AC = 24 cm and BD = 10 cm.


We know that diagonals of a rhombus bisect each other at 90°.


⇒ ∠AOB = 90°, OA = 12 cm and OB = 5 cm


∴ ΔAOB is a right-angled triangle.


Applying Pythagoras theorem,


BA2 = BO2 + AO2


⇒ BA 2 = 52 + 122


⇒ BA2 = 25 + 144 = 169


⇒ BA = AD = CD = BC = 13 cm


∵Sides of a rhombus are equal.


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