ΔABC ~ ΔDEF such that ar(ΔABC) = 64 cm2 and ar(ΔDEF) = 169 cm2. If BC = 4 cm, find EF.

We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.


i.e. ar(ABC)/ar(DEF) = (BC/EF)2


Substituting the given values, we get


64cm2/169cm2 = (4cm/EF cm)2


64/169 = 16/EF2


EF2 = 42.25


EF = 6.5cm


6.5 cm


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