ΔABC ~ ΔDEF such that ar(ΔABC) = 64 cm2 and ar(ΔDEF) = 169 cm2. If BC = 4 cm, find EF.
We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
i.e. ar(ABC)/ar(
DEF) = (BC/EF)2
Substituting the given values, we get
⇒ 64cm2/169cm2 = (4cm/EF cm)2
⇒ 64/169 = 16/EF2
⇒ EF2 = 42.25
⇒ EF = 6.5cm
6.5 cm