A man goes 24 m due west and then 10 m due north. How far is he from the starting point?
Since the man goes C to A = 24 m west and then A to B = 10 m north, he is forming a right angle triangle with respect to starting point C.
His distance from the starting point can be calculated by using Pythagoras theorem
(AC)2 = (AB) 2 + (BC)2
⇒ (AC)2 = (24)2 + (10)2
⇒ (AC)2 = 576 + 100
⇒ (AC)2 = 676
⇒ AC = 26
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