In the given figure, O is a point inside m a ΔMNP such that ∠MOP = 90°, OM = 16 cm and OP = 12 cm. If MN = 21 cm and ∠NMP = 90° then NP = ?
The ΔMOP is right angled at O so MP is hypotenuse
(MP)2 = (OM)2 + (OP)2
(MP)2 = (16) 2 + (12)2
(MP)2 = 400
MP = 20 cm
Δ NMP is right angled at M so NP is the hypotenuse so
(NP)2 = (21)2 + (20)2
NP = 29