In a rhombus of side 10 cm, one of the diagonals is 12 cm long. The length of the second diagonal is
Since the diagonals of the rhombus bisects each other at 90°
∴ DO = OB = 6 cm
∠ AOD = ∠ DOC = ∠ COB = ∠BOA = 90°
Δ AOD is right angled Δ with
AD = 10 cm (given)
OD = 6 cm
∠ AOD = 90°
So DA = 10 = hypotenuse
(DA)2 = (DO)2 + (AO)2
100 – 36 = (AO)2
8 = AO
∴ AC = 16
16