In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is
Perimeter of Δ ABC = AB + BC + CA
= 9 + 6 + 7.5
= 22.5 cm
Since the Δ ABC ∼ 
DEF
= 
(ratio of perimeter of triangles is equal to the ratio of the sides of the triangle )
= 
= 
= 30 cm
29