In the given figure, ∠ BAC = 90° and AD ⊥ BC. Then,

Question

Philoid · Accepted Answer

∠ABD + ∠ BAD = 90°

∠ ABD + (90-∠CAD) = 90°
∠ ABD = ∠ DAC
In ΔBDA and Δ ADC,
∠ ABD = ∠ CAD
∠ BDA = ∠ ADC = 90°
Therefore, ΔBDA and Δ ADC are similar by AAA.
BD.CD = AD²
Therefore the correct option is (c).

In the given figure, ∠BAC = 90° and AD ⊥ BC. Then,