Match the following columns:
Column I | Column II |
A. A man goes 10 m due east and then 20 m due north. His distance from the starting point is ……..m. | P. 25√3 |
B. In an equilateral triangle with each side 10 cm, the altitude is ……cm. | Q. 5√3 |
C. The area of an equilateral triangle having each side 10 cm is …….cm2. | R. 10√5 |
D. The length of diagonal of a rectangle having length 8 m and breadth 6 m is ……..m. | S. 10 |
A)
The man starts from A, goes east 10m to B. From B, he goes 20m to C.
AC2 = AB2 + BC2
AC2 = 102 + 202
AC2 = 100 + 400 = 500
AC = √ 500 = 10√5
Therefore, (A)-(R)
B)
In ΔABD,
AB2 = AD2 + BD2
102 = AD2 + 52
AD2 = 100-25 = 75
AD = √ 75 = 5√3
Therefore, (B)-(Q)
C)
Area of an equilateral triangle = cm
Therefore,(C)-(P)
D)
In ΔABC,
AC2 = AB2 + BC2
AC2 = 62 + 82
AD2 = 36 + 64 = 100
AD = √ 100 = 10
Therefore, (D)-(S)