Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their feet is 12 m then the distance between their tops is
Given: Height of pole 1 = 6 m
Height of pole 2 = 11 m
Distance between the feet of pole 1 and pole 2 = 12 m
To find: Distance between the tops of both the poles
Clearly, In ∆ ADE,
DE = 5 m
AD = 12 m
Also, ∠ADE = 90° [∵ Both the poles stand vertically upright]
∴ By applying Pythagoras theorem, we have
AE2 = AD2 + DE2
⇒ AE2 = (12)2 + (5)2 = 144 + 25 = 169
⇒ AE = √169 = 13 m