In a trapezium ABCD, it is given that AB || CD and AB = 2CD. Its diagonals AC and BD intersect at the point 0 such that ar (ΔAOB) = 84 cm2. Find ar (ΔCOD).
Given: AB ∥ CD
AB = 2CD ……….(i)
ar (∆ AOB) = 84 cm2
To find: ar (∆ COD)
In ∆ AOB and ∆ COD,
∠ AOB = ∠ COD [Vertically Opposite angles]
∠ OAB = ∠ OCD [Alternate interior angles (AB ∥ CD)]
∠ OBA = ∠ ODC [Alternate interior angles (AB ∥ CD)]
⇒ ∆ AOB ∼ ∆ COD [By AAA criterion]
Now,
∵ The ratios of the areas of two similar triangles are equal to the ratio of squares of any two corresponding sides.
∴ We have
Also, from (i), we have