Find the length of each side of a rhombus whose diagonals are 24 cm and 10 cm long.

Given: Length of one of the diagonals = 24 cm

Length of the other diagonal = 10 cm


To find: Length of the side of the rhombus



The length of all sides of rhombus is equal.


Let side of rhombus ABCD be x cm.


Also, we know that the diagonals of a rhombus are perpendicular bisectors of each other.


AO = OC = 12 cm and BO = OD = 5 cm


Also, AOB = BOC = COD = AOD = 90°


Now, consider ∆ AOD


AO = 12 cm and OD = 5 cm


AOD = 90°


So, using Pythagoras theorem, we have


AD2 = AO2 + OD2 = 122 + 52 = 144 + 25 = 169


AD = √169 = 13 cm


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