Let x + 2 =

⇒ x + 2 = A(2x) + B

Now, equating the coefficients of x and constant term on both sides, we get,

2A = 1

⇒ A =

B = 2

⇒ x + 2 = (2x) + 2

⇒

⇒

Now,

Let x² - 1 = t

⇒ (2x)dx = dt

⇒

⇒

And

⇒