Mathematics Part-II

Book: Mathematics Part-II

Chapter: 7. Integrals

Subject: Maths - Class 12th

Q. No. 19 of Exercise 7.4

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19

Integrate the functions.

Let 6x + 7 =

⇒ 6x + 7 = A(2x - 9) + B


Now, equating the coefficients of x and constant term on both sides, we get,


2A = 6


⇒ A = 3


-9A + B = 7


⇒ B = 34


⇒ 6x + 7 = 3 (2x - 9) + 34


⇒


⇒


Now,


Let x2 – 9x + 20 = t


⇒ (2x - 9)dx = dt


----------(1)


And


x2 – 9x + 20 =


⇒


⇒


…(2)


Thus, from (1) and (2), we get,


⇒


⇒


19

Chapter Exercises

Exercise 7.2
Exercise 7.4
Exercise 7.5
Exercise 7.3
Exercise 7.1
Exercise 7.6
Exercise 7.8
Exercise 7.9
Exercise 7.10
Exercise 7.11
Exercise 7.7
Miscellaneous Exercise

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