Integrate the functions.

Let 5x + 3 =

5x + 3 = A(2x + 4) + B


Now, equating the coefficients of x and constant term on both sides, we get,


2A = 5


A =


4A + B = 3


B = -7


5x + 3 =


Now,



Now, let us consider,


Let x2 +4x + 10= t


(2x + 4) dx= dt


… (1)


And, Now let us consider,




…(2)


using eq. (1) and (2), we get,




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