Let

⇒ x = A(x + 2) + B(x +1)

On comparing the coefficients of x and constant term, we get,

A + B = 1

2A + B = 0

On solving above two equations, we get,

A = -1 and B = 2

Thus,

= -log|X + 1| + 2log|x + 2| + C

= log (x+2)² – log |x + 1| + C