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Integrate the rational functions.
⇒ 3x -1 = A(x-2)(x-3) + B(x-1)(x-3) + C(x-1)(x-2) …(1)
Substituting x = 1, 2 and 3 respectively in equation (1), we get,
A = 1, B = -5 and C = 4
= log|x -1| -5log|x-2| + 4log|x-3| + C
[Hint: multiply numerator and denominator by xn-1 and put xn=t]
[Hint: Put ex = t]