Let

⇒ x = A(x - 1)(x + 2) + B(x + 2) + C( x – 1)² …(1)

Substituting x = -1 in equation (1), we get,

B =

Equating the coefficients of x2 and constant term, we get,

A + C = 0

-2A + 2B + C = 0

A = and c =

Thus,